bash pattern matching echo *[! '/' ] doesn't work

Tags

beginners

Top Forums UNIX for Dummies Questions & Answers bash pattern matching echo *[! '/' ] doesn't work

07-15-2006

Registered User

16, 0

Join Date: Jul 2006

Last Activity: 1 October 2006, 10:15 AM EDT

Posts: 16

Thanks Given: 0

Thanked 0 Times in 0 Posts

bash pattern matching echo *[! '/' ] doesn't work

without using ls, just using echo so purely pattern matching

I can say echo */ <-- lists directories

but how would I match files? surely something like *!/ or *[!/] but neither work ?

it seems like there isn't much that I can put in [ ] but surely i should be able to put any ascii character. but how?

thanks

james hanley

View Public Profile for james hanley

Find all posts by james hanley

07-16-2006

Registered User

360, 9

Join Date: Jun 2006

Last Activity: 10 December 2011, 9:33 AM EST

Posts: 360

Thanks Given: 0

Thanked 9 Times in 8 Posts

$ find -maxdepth 1 -type f -exec echo {} \;

Hitori

View Public Profile for Hitori

Find all posts by Hitori

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

[Bash] passing variables to executable doesn't work

Bash version 4.4.20 / Ubuntu 16.0.4 Hello, I tried to write a script that gathers some data and passes them to an executable. The executed application answers with an error. The echo output in the script returns correct values. If I copy/paste the last echo command, it get's executed...

2. UNIX for Beginners Questions & Answers

Bash diff date doesn't work

Hi everyone, I've an issue trying to soustracte two dates, e.g: d1=$(date -d "Nov 18, 2017" +%s) d2=$(date +%s) # Today we are 2017-11-16 echo "$(( (d1 - d2) / 86400 ))" Output: 1 I don't understand why it doesn't work. for me, it should give "18 - 16 = 2". Much appreciated...

3. Shell Programming and Scripting

Why regex pattern doesn't work in find?

$ find /opt/data_* -maxdepth 3 -type d -name "main*" 2> /dev/null /opt/data_025/maindblogs /opt/data_026/maindblogs /opt/data_027/maindblogs /opt/data_028/maindblogs $ find /opt/data_* -maxdepth 3 -type d -name "rvlogs*" 2> /dev/null /opt/data_002/prod/rvlogs2_archive...

4. Shell Programming and Scripting

pipe to grep doesn't work in bash script

Hi, I'm trying to write a script that checks gvfs to see if a mount exists so I can run it from network-manager's status hooks. I thought I'd pipe the output of gvfs-mount -l to grep for the particular mounts I care about. When I do this in a bash script: cmnd="gvfs-mount -l | grep -i...

5. Shell Programming and Scripting

echo doesn't work right

Hi,when I run my first shell script,I got something that doesn't work right. I wrote this code in the script. echo -e "Hello,World\a\n"But the screen print like this: -e Hello,World The "-e" wasn't supposed to be printed out. Can anyone help me out?:wall: Many thanks!:)

6. HP-UX

pgrep doesn't perform full command line pattern matching

Hi! I need to get PID of some particular process and I wonder if I can use pgrep tool for this purpose. The problem is that pgrep doesn't perform pattern matching on the whole command line, even if I use -f key. Parsing output of ps command is not quite convenient... Also deamon, which PID I need...

7. Ubuntu

set completion-ignore-case on doesn't work in bash

completion-ignore-case option doesn't work in my version: /home/user $ echo $BASH_VERSION 3.2.48(1)-release /home/user $ ls -l * -rw-r--r-- 1 user user 0 2009-10-18 00:09 somefile -rw-r--r-- 1 user user 0 2009-10-18 00:09 Somefile /home/user $ set completion-ignore-case on But when I...

8. Shell Programming and Scripting

shell script, echo doesn't work

#!/bin/sh something(){ echo "Inside something" echo $1 $2 } val=$(something "Hello " "world") Output expected: Inside somethingHello world But it's not echoing.

9. Shell Programming and Scripting

echo $PWD doesn't work

I have entry in the my .profile like below, but still i see $PWD is not defied in my system export PS1=$LOGNAME@`hostname`':'$PWD'>' echo $PWD also gives me nothing, my env list also give no entry for PWD.Can someone help me setting PWD variable. I use /bin/sh

10. Shell Programming and Scripting

Perl cmds doesn't work in Bash shell . Plz help

Hi everyone, I have a Linux OS in my PC (older version 9). Its default shell is bash. Whenever I try to run some Perl program it throws error ! eg, if I run this simple PERL program , #!/usr/bin/perl printf "\lHello \n"; $var=3 ; printf $var; @list=(1,2,3); printf "@list";...

UNIX for Dummies Questions & Answers