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return previous line for pattern match

 
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# 1  
Old 06-26-2006
return previous line for pattern match
Hi,

Need some idea on file processing, I have file like below,

Code:
Processing al sources ...
...No value found : 
CHECK. 
Completed comparing all  sources.
Comparing schedulers...
Processing al targets ...
...No value found :

From above I need to extract the line where "No value found" is available, which is simple, but I also wanna print the line before i.e
Code:
Processing al sources ...
...No value found : 
Processing al targets ...
...No value found :

Can sometell me how to go about this ?

Thanks
# 2  
Old 06-26-2006
You never mentioned your OS. If you have GNU grep, the use

Code:
grep -B 1 "No value found" file

# 3  
Old 06-26-2006
If your grep has no -B (Aix hasn't) then:
Code:
sed -n -e 'N; /No Value Found/p' yourfile.txt

cheers
# 4  
Old 06-26-2006
sorry guys, didn't give enough information,this is in suse linux,

sed -n -e 'N; /No match/p' $1 worked perfect.... thanks..
Last edited by braindrain; 06-26-2006 at 12:40 PM..
# 5  
Old 12-08-2008
Hi,
i tried
sed -n -e 'N; /No Value Found/p' yourfile.txt

but it only prints the previous line for the first match only.
thereafter only matching lines are printed and not their previous lines.

Thanks,
-srinivas yelamanchili
 
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