awk : dynamic output flatfile filename

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# 1  
Old 06-02-2016
awk : dynamic output flatfile filename


I'm using the awk command to insert empty columns on a tab delimited flatfile - which works fine -
=> But I'm not able to manage dynamicaly the filename of the awk output based on the source flatfile filename

I have 3 source flatfile:

And I would like to output the result of the awk command to

Below the awk command which is working for inserting empty columns but I'm not able to manage dynamically the target flatfile filename

awk -F"\t" '$6="\t" $6' OFS="\t" *flatfile* > flatfile_Jan-2016.dat


Moderator's Comments:
Mod Comment Please use code tags as required by forum rules!

Last edited by RudiC; 06-02-2016 at 01:04 PM.. Reason: Added code tags.
# 2  
Old 06-02-2016
Try (untested):
awk -F"\t" '{$6="\t" $6; print > ("new" FILENAME)' OFS="\t" *flatfile*

# 3  
Old 06-02-2016
Originally Posted by RudiC
Try (untested):
awk -F"\t" '{$6="\t" $6; print > ("new" FILENAME)' OFS="\t" *flatfile*

Note that to avoid processing newflatfile_Mon-YEAR.csv files if you run this script multiple times, you probably want to just use flatfile* instead of *flatfile* as the filename matching pattern in your script.
# 4  
Old 06-06-2016
thank you all, it is working like a charm!
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