Replace string and create new file multiple times


 
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# 1  
Replace string and create new file multiple times

First of all, apologies if this has already been answered elsewhere. I haven't quite been able to find what I'm looking for yet, so hopefully this won't come across as repetition.

I have a file consisting of ~100 nearly identical lines, each of which contains multiple instances of the string I need to replace. Let's say the string is simply "001". Each instance of the string within a single line has a slightly different pre/suffix that can be used for search purposes. I know sed is capable of addressing this, but I'm not sure how to proceed with the following steps...

I need to create a new file where the 001 is replaced with 002, while everything else in the line remains unchanged. This will go on until, say, 300 - thus generating 300 different files, each of which needs to be saved separately.

So the first file contains a list like this:

Code:
-file1 001.txt -file2 blah1.txt -outputx x001blah1 -outputy y001blah1
-file1 001.txt -file2 blah2.txt -outputx x001blah2 -outputy y001blah2
-file1 001.txt -file2 blah3.txt -outputx x001blah3 -outputy y001blah3

...saved as list001.txt. I need to replace the three instances of 001 with 002 and save that file as list002.txt, which would look like this:

Code:
-file1 002.txt -file2 blah1.txt -outputx x002blah1 -outputy y002blah1
-file1 002.txt -file2 blah2.txt -outputx x002blah2 -outputy y002blah2
-file1 002.txt -file2 blah3.txt -outputx x002blah3 -outputy y002blah3

And so on and so forth until list300.txt (this number is pre-defined).

If I were to do this manually, it would require searching and replacing over a thousand times. Is there a single script I can use to find, replace, and create all 300 files, without having to make and modify each one individually?

Last edited by pseudo.seppuku; 05-25-2016 at 01:23 PM..
# 2  
To be honest, these 300 lists sound like something that could be replaced with a single script, if you could tell us what you're actually trying to do.
# 3  
Each line corresponds to an individual command for a program designed to compare two different files (e.g. 001/blah1, 001/blah2, 001/blah3, etc.). I can't stray from the basic format described in my first post or carry out multiple comparisons using a single command. Given that I have a few hundred files to compare, I'm looking for a quicker way to generate this list of commands.

I'll join all 300 files together later on using cat, but at this stage, I figured it might be easier (from a scripting standpoint) to create a new file after each replacement, rather than continually append a set of modified lines to the end of one very long file.
# 4  
Hello pseudo.seppuku,

Welcome to forums. Could you please try following and let me know if this helps you.
Code:
for file in *.txt
do
     let "i = i + 1"
     awk -vI=$i '{gsub(/001/,"002",$0);VAL=sprintf("%s%02d",FILENAME,I);print >> VAL}' $file
done

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
# 5  
Thank you! That certainly did the trick. The only caveat is that the new file is called list001.txt01 instead of list002.txt.

Aside from the file-naming convention... is there a way to do this multiple times in a row, using a single script? In other words, i = i + (1..299) - each time saved as a new file?
# 6  
Try
Code:
awk '
        {ARR[NR] = $0}
END     {for (i=1; i<=MAX; i++) {if (FN) close (FN)
                                 TCNT = sprintf ("%03d", i)
                                 FN = FILENAME TCNT ".txt" 
                                 for (j=1; j<=NR; j++)  {T = ARR[j]
                                                         gsub (/001/, TCNT, T)
                                                         print T > FN
                                                        }
                                }
        }
' MAX=3 file
cf *.txt
file001.txt:
-file1 001.txt -file2 blah1.txt -outputx x001blah1 -outputy y001blah1
-file1 001.txt -file2 blah2.txt -outputx x001blah2 -outputy y001blah2
-file1 001.txt -file2 blah3.txt -outputx x001blah3 -outputy y001blah3
file002.txt:
-file1 002.txt -file2 blah1.txt -outputx x002blah1 -outputy y002blah1
-file1 002.txt -file2 blah2.txt -outputx x002blah2 -outputy y002blah2
-file1 002.txt -file2 blah3.txt -outputx x002blah3 -outputy y002blah3
file003.txt:
-file1 003.txt -file2 blah1.txt -outputx x003blah1 -outputy y003blah1
-file1 003.txt -file2 blah2.txt -outputx x003blah2 -outputy y003blah2
-file1 003.txt -file2 blah3.txt -outputx x003blah3 -outputy y003blah3

This User Gave Thanks to RudiC For This Post:
# 7  
Quote:
Originally Posted by pseudo.seppuku
Thank you! That certainly did the trick. The only caveat is that the new file is called list001.txt01 instead of list002.txt.
Aside from the file-naming convention... is there a way to do this multiple times in a row, using a single script? In other words, i = i + (1..299) - each time saved as a new file?
Hello pseudo.seppuku,

Could you please try following and let me know if this helps, not tested though.
Code:
for file in *.txt; do let "i = i + 1"; awk -vI=$i '{gsub(/001/,"002",$0);VAL=sprintf("%02d",I);print >> FILENAME VAL;}' $file; done

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
 

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