Using Grep to Define a Variable


 
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# 1  
Old 10-12-2001
Using Grep to Define a Variable

I am using korn shell unix.

I have a script that I am working with to do a check for me using a text file.



#finds "Time" from the text file and cuts the second field from the #line

A= grep Time test.txt | cut -f2


# the "#Missing" is being pulled from the second field of the text #file

if [ "$A" = #Missing ]
then
echo "page me"
fi



My problem is that I am unable to get the 'echo "page me"' to echo back onto the screen. This tells me that the check isn't successful- or at least that is what I think it is telling me.

My if statement may be incorrect- I've tried '-eq', but no luck there either.

I'm also not certain if I can use grep to try and define a variable. I've even attempted to use awk. Everything works on the command line, by itself (like running the grep command).

Anyone have any ideas? I'm pretty new at Unix.

Thanks,

Chris
# 2  
Old 10-12-2001
I tried it this way...

I'm sure there are 100 different ways of accomplishing this, but this worked for me:

#!/bin/ksh

A=`grep Time test.txt | cut -f2`

if [ $A = \#Missing ]
then
echo "page me"
fi
 
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