UNIX for Dummies Questions & Answers

Hi,

I'm running atq for a user and its showing 2 'at' jobs in the queue to start at a later time.

Code:

> atq

Is there any way i can find out the creation date/time of these jobs?

and ideally what job created them and what script(s) they are going to run?

All i can see is the job number and the job start time from the atq command. Cant see anything in the man pages.

Thanks

As you mentioned atq can show you defined jobs (tasks). The for each defined job name you can use "at -c" to "cat" what the job is going to attempt to do. I don't think there is a way to get the time of insertion of a job.

If you look at the man page for at on your system, it will probably give you the name of the directory containing the queued at jobs (or include a SEE ALSO entry for another man page that give you that information). If you look in that directory, the name of the file may include the time when the job is to be run and the timestamp on the file will probably be the time when the at jobs were created or last changed. But, it won't give you any indication what created them.

Unlike cron jobs, at jobs store the complete environment of the process that created them. You can typically figure the owner of the process by examining the environmental variables included in the the job file.