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Multiple variables to be passed in a loop

 
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# 1  
Old 07-28-2015
Multiple variables to be passed in a loop
Hi,

I need to pass the multiple values of src1 to another variable. I managed to print it but not sure how to assign it to a variable in a loop.

Code:
src1=01,02,03
echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'

I need to pass the value as
src2=01
src2=02
src2=03

Thanks
Shashi
# 2  
Old 07-28-2015
Not sure what you require. Would this fit your needs:
Code:
IFS=","; for i in $src1; do src2=$i; echo $src2; done

This User Gave Thanks to RudiC For This Post:
shash
# 3  
Old 07-28-2015
You might want to give this a try:

Code:
while IFS="=" read part1 part2 ; do
     print - "part1 is: $part1   part2 is $part2"
done < /path/to/file

Where file might contain:

Code:
part1=part2
a=b
foo=bar

Instead of a file you can use a pipeline or a here-document as well, i.e.:

Code:
some-command | while IFS="=" read part1 part2 ; do
     print - "part1 is: $part1   part2 is $part2"
done


The interesting part of the code is this:

Code:
IFS="<some-char>" read var1 var2 [var3....]

Setting the IFS variable to some character means the input is split up into "words" at exactly this character. The variables ("var1", "var2", ...) are assigned these words one after the other. If your input would look like this:

Code:
foo:bar:bas
bla:blub:whatever
1:2:3

You could write:
Code:
IFS=":" read first second third
echo $first
echo $second
echo $third

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
shash
# 4  
Old 07-28-2015
can you explain what you want as output?

you can assign simply
Code:
y=`echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'`

but not sure what youu mean by variable in a loop
# 5  
Old 07-29-2015
Apologies for not being clear enough in posting my requirements. Thanks for all your inputs. I have now got what I wanted.
 
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