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Rename files based on a list


 
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# 1  
Rename files based on a list

Hi,
I have a directory with a lot of files like this:
Code:
a.bam
b.bam
c.bam

I like to rename these files based on a list where the name of the files in the first column will be replasced by the names in the second column. Here is my list which is a tab-delimited text file:
Code:
a    x
b    y
c    z

The output should be like this:
Code:
x.bam
y.bam
z.bam

Thanks in advance
# 2  
Try:
Code:
while IFS='	' read from to
do
  [ -f "$from.bam" ] && mv -- "$from.bam" "$to.bam"
done < list

where the TAB Character can entered as CTRL-V TAB in vi..

Or
Code:
tab=$(printf "\t")
while IFS=$tab read from to
do
  [ -f "$from.bam" ] && mv -- "$from.bam" "$to.bam"
done < list

In bash of ksh93 you can use $'\t'

Last edited by Scrutinizer; 04-28-2015 at 06:26 PM..
# 3  
Quote:
Originally Posted by Scrutinizer
Try:
Code:
while IFS='	' read from to
do
  [ -f "$from.bam" ] && mv -- "$from.bam" "$to.bam"
done < list

where the TAB Character can entered as CTRL-V TAB in vi..

Or
Code:
tab=$(printf "\t")
while IFS=$tab read from to
do
  [ -f "$from.bam" ] && mv -- "$from.bam" "$to.bam"
done < list

In bash of ksh you can use $'\t'
Shouldn't the line marked in red above be:
Code:
while IFS="$tab" read from to

?
# 4  
Hi Don, it is a variable assignment and $tab is therefore exempt from field splitting after expansion...
This User Gave Thanks to Scrutinizer For This Post:
# 5  
Thanks, it worked
 

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