UNIX for Dummies Questions & Answers

I've got a ksh script that works like a charm when I run it manually. When I set it up in a cron, I keep getting this error in my log:

syntax error at line 90: `$' unexpected

Here's my snippet of code starting at line 90:

while [[ ! -e $DATA_DIR/tuscprof.dat && $(date '+%H:%M') < 10:00 ]]
do
sleep 900
done

What's the problem?

In the first line of your script put:

Code:

#! /usr/bin/ksh

It already has this line at the top, after the path:

. /usr/local/bin/TEST.env

PATH=/usr/lbin:/usr/bin:/etc:/usr/sbin:/usr/ucb:/sbin:/bin:/usr/local/bin:$ORACLE_HOME:$ORACLE_HOME/bin:/apps:.; export PATH

SHELL=/bin/ksh
export SHELL

Mind you, this was not my original script so I don't know much about certain portions of it, including this one

That's not going to help you. You need to put the line I suggested at the First line in the script.

That's not what dangral is refering to.

The very first line of the script needs to be #! /usr/bin/ksh. This forces the execution shell to become a Korn shell and not SH as is your case. The specific line cannot come after anything and it must be line 1.

My cron job worked all weekend. Thanks guys!