UNIX for Dummies Questions & Answers

My unix version is IBM AIX Version 6.1

I tried google my requirement and found the below answer,

Code:

find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20"

But newer command is not working in AIX version 6.1 unix

I have given my requirement below:

Input:

Code:

atr files:

file_atr1.txt     --created on feb 01 2015
file_atr2.txt    --created on feb 10 2015
file_atr3.txt    --created on feb 16 2015

ses files:

file_ses1.txt    --created on feb 01 2015
file_ses2.txt    --created on feb 10 2015
file_ses3.txt    --created on feb 16 2015

I need to get the count of two files separately based on date range. If the count matches then, I should set the flag as 'Y' else 'N'

For eg: I am giving the date range as start date: feb 01 2015 and end date: feb 15 2015, i should be getting 2 files
from atr file list and 2 files from ses file list for the date range mentioned above.Since the count of two file list matches then the flag should be set as 'Y'

Output:

Code:

atr files:

file_atr1.txt     --created on feb 01 2015
file_atr2.txt    --created on feb 10 2015

ses files:

file_ses1.txt    --created on feb 01 2015
file_ses2.txt    --created on feb 10 2015

Count of atr files: 2
Count of ses files: 2

Out_Flag = 'Y'

Moderator's Comments:

Please wrap all code, files, input & output/errors in CODE tags. It makes the easier to read and preserves multiple spaces. I've had to guess at where to mark the input & output so adjust it if required. Press the Edit button in the bottom right of this post