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How Much Space Before 1st Partition?

 
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# 15  
Old 11-25-2014
1000kb is "drivermaker's megabytes", invented to inflate the apparent capacity of the drives they sell.
# 16  
Old 11-25-2014
Hey Guys, thanks for the reply about the block stuff...

So if I run the dd command(s) you gave I get this output below...

Up to 512-bytes:
Code:
# dd if=/dev/sdc bs=512 count=1 | od -c
1+0 records in
1+0 records out
0000000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
512 bytes (512 B) copied0000660  \0  \0  \0  \0  \0  \0  \0  \0 006 311 003   U  \0  \0 200    
, 0.00276015 s, 185 kB/s
0000700   !  \0 203     004      \0  \b  \0  \0 004 330  \a  \0  \0   @
0000720   !     203  \0 301 212  \0 350  \a  \0  \v   / 326  \0  \0 003
0000740 372 212 202 376 377 307  \0 030 336  \0 310   1 017  \0  \0  \0
0000760  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0   U 252
0001000

All the way to 2048:
Code:
# dd if=/dev/sda bs=512 count=4 | od -c 
# dd if=/dev/sdc bs=512 count=4 | od -c 
0000000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
4+0 records in
4+0 records out
*
2048 bytes (2.0 kB) copied0000660  \0  \0  \0  \0  \0  \0  \0  \0 006 311 003   U  \0  \0 200    
0000700   !  \0 203     004      \0  \b  \0  \0 004 330  \a  \0  \0   @
, 0.00280096 s, 731 kB/s
0000720   !     203  \0 301 212  \0 350  \a  \0  \v   / 326  \0  \0 003
0000740 372 212 202 376 377 307  \0 030 336  \0 310   1 017  \0  \0  \0
0000760  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0   U 252
0001000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
0002000 321  \0       @  \0 200 220  \0  \0  \0  \0  \0   ,   t 220  \0
0002020       t 220  \0  \0   t 220  \0  \0  \0  \0  \0  \0  \0  \0  \0
0002040  \0   p 220  \0  \0 200  \0  \0  \0  \0  \0  \0 322  \0   `   @
0002060 314  \0   \ 004 002  \f   @   h  \0 300   ?   ? 002  \f   @   l
0002100  \0   0 374 003 002  \f   @   p 017 377 300  \0 002  \f   @   t
0002120   ? 360  \0  \0 002  \f   @   x  \0 377 363  \0 002  \f   @   |
0002140 017  \0  \0 303 002  \f   @ 200  \0  \0 003 377 002 016  \0 020
0002160 360  \0  \0 317 002 016  \0 030  \0 177  \0 177 002 016  \0 034
0002200  \0 177  \0 177 002  \f   @   `  \0  \0  \0 373  \0  \0  \0  \0
0002220  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
0004000

Is it safe to say here that the asterisks in the output above denote EMPTY space in that area of the disk..?

Also, so I'm clear on the sector/block size stuff.
If this below is the output for fdisk, and the START is 2048 and the UNIT size 512 bytes.
So for every "1 Unit" out of the 2048 START point, that would be: .5kb * 2048 = 1024 Kb... Is that right?
Code:
# fdisk -l /dev/sdc

Disk /dev/sdc: 7969 MB, 7969177600 bytes
255 heads, 63 sectors/track, 968 cylinders, total 15564800 sectors
Units = sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disk identifier: 0x5503c906

   Device Boot      Start         End      Blocks   Id  System
/dev/sdc1   *        2048      516099      257026   83  Linux
/dev/sdc2          518144    14554890     7018373+  83  Linux
/dev/sdc3        14555136    15550919      497892   82  Linux swap / Solaris

Thanks Again for the help, much appreciated!

Thanks,
Matt
# 17  
Old 11-25-2014
Quote:
Originally Posted by RudiC
512 bytes = 1/2 kB
1024 bytes = 1 kB
This now is where discrepancies start:
1024 kB = 1 M?B (sometimes MiB)
1000 kB = 1 M?B
etc...
Oops! Smilie Made corrections
Sorry mrm5102

I'll try again. Smilie
Quote:
.5kb * 2048 = 1024 Kb... Is that right?
.5 * 2048 Kb = 1024 Kb... Is that right? Yes
.5kb(512 bytes) * 2048 = 1048576 bytes (1.048 Mb)
Last edited by ongoto; 11-25-2014 at 08:13 PM.. Reason: added quote
# 18  
Old 11-25-2014
Quote:
Originally Posted by mrm5102
...

Up to 512-bytes:
Code:
# dd if=/dev/sdc bs=512 count=1 | od -c
1+0 records in
1+0 records out
0000000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
512 bytes (512 B) copied0000660  \0  \0  \0  \0  \0  \0  \0  \0 006 311 003   U  \0  \0 200    
, 0.00276015 s, 185 kB/s
0000700   !  \0 203     004      \0  \b  \0  \0 004 330  \a  \0  \0   @
0000720   !     203  \0 301 212  \0 350  \a  \0  \v   / 326  \0  \0 003
0000740 372 212 202 376 377 307  \0 030 336  \0 310   1 017  \0  \0  \0
0000760  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0   U 252
0001000

All the way to 2048:
Code:
# dd if=/dev/sda bs=512 count=4 | od -c 
# dd if=/dev/sdc bs=512 count=4 | od -c 
0000000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
4+0 records in
4+0 records out
*
2048 bytes (2.0 kB) copied0000660  \0  \0  \0  \0  \0  \0  \0  \0 006 311 003   U  \0  \0 200    
0000700   !  \0 203     004      \0  \b  \0  \0 004 330  \a  \0  \0   @
, 0.00280096 s, 731 kB/s
0000720   !     203  \0 301 212  \0 350  \a  \0  \v   / 326  \0  \0 003
0000740 372 212 202 376 377 307  \0 030 336  \0 310   1 017  \0  \0  \0
0000760  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0   U 252
0001000  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
0002000 321  \0       @  \0 200 220  \0  \0  \0  \0  \0   ,   t 220  \0
0002020       t 220  \0  \0   t 220  \0  \0  \0  \0  \0  \0  \0  \0  \0
0002040  \0   p 220  \0  \0 200  \0  \0  \0  \0  \0  \0 322  \0   `   @
0002060 314  \0   \ 004 002  \f   @   h  \0 300   ?   ? 002  \f   @   l
0002100  \0   0 374 003 002  \f   @   p 017 377 300  \0 002  \f   @   t
0002120   ? 360  \0  \0 002  \f   @   x  \0 377 363  \0 002  \f   @   |
0002140 017  \0  \0 303 002  \f   @ 200  \0  \0 003 377 002 016  \0 020
0002160 360  \0  \0 317 002 016  \0 030  \0 177  \0 177 002 016  \0 034
0002200  \0 177  \0 177 002  \f   @   `  \0  \0  \0 373  \0  \0  \0  \0
0002220  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0  \0
*
0004000

Is it safe to say here that the asterisks in the output above denote EMPTY space in that area of the disk..?
No. There is no such thing as empty space on a character special file. The asterisk in the output from od means that the lines of output replaced by the asterisk are duplicates of the output shown on the line above. In this case, they all happen to be NUL bytes, but they could just as easily represent repeated occurrences of the characters "0123456789ABCDEF" (or any other sequence of 16 bytes).
 
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