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Passing Shell Variable to awk

 
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# 1  
Old 10-22-2014
Passing Shell Variable to awk
Hello All,

May i please why my shell variable is not getting passed into awk script.

HTML Code:
#!/bin/bash -vx

i="1EB07C50"

/bin/awk -v ID="$i" '/ID/ {match($0,/ID/);print substr($0,RSTART,RLENGTH)}' /var/log/ScriptLogs/keys.13556.txt
Thank you.
# 2  
Old 10-22-2014
It is, actually, but /ID/ is not a variable. Try this:

Code:
echo asdf | awk '{ print /qwerty/ }'

/qwerty/ is an expression meaning 'check if the line matches this'. It becomes 1 if it does, 0 if not. It's not a variable.

You can move match outside the block to just do the check with it instead of /ID/. It also returns 1 on success and 0 on failure.

Code:
/bin/awk -v ID="$i" ' match($0,ID) {print substr($0,RSTART,RLENGTH)}' /var/log/ScriptLogs/keys.13556.txt

This User Gave Thanks to Corona688 For This Post:
Ariean
 
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