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Sed help please


 
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# 1  
Sed help please

Hi,

I have a file which may look like this

. ..
.Xauthority .cshrc
.exrc .history
.login .profile
.sh_history .ssh
.sudata
andy cron.20031210
cron.oa cron.oa.backup2003121


I would like to use sed to remove any words etc beginning with . (dot) so that the file would look like this.


andy
cron.20031210
cron.oa
cron.oa.backup2003121


I have tried many combinations of search patterns in sed but cannot work out how to do it.

Please help!

Cheers
Helen Smilie
# 2  
Code:
sed -e '/^\./d'

# 3  
Just noticed that this deletes the whole line, I would like it to just delete the word. Its quite possible the file may look like this:

. ..
.Xauthority .cshrc
.exrc .history
.login .profile
.sh_history .ssh
.sudata andy

cron.20031210 cron.oa cron.oa.backup2003121


In which case I would not want the word "andy" deleting.

Thanks
Helen

Last edited by Bab00shka; 02-08-2006 at 11:16 AM..
# 4  
Code:
tr ' ' '\n' < myFile.txt | sed '/^[.]/d'

# 5  
Thanks Vergersh99,

That worked fine Smilie
Cheers
Helen
# 6  
and with just awk,

Code:
awk -F" " ' !/^\./ { printf $1 "\n" $2 "\n" }' file

# 7  
Quote:
Originally Posted by matrixmadhan
and with just awk,

Code:
awk -F" " ' !/^\./ { printf $1 "\n" $2 "\n" }' file

the above is limited to each row having max of two words not begining with "."(dot). use for loop to overcome this limitation..
awk -F" " ' !/^\./ {for(i=1;i<=NF;i++) {printf $i " " } printf "\n" }' words.
 

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