UNIX for Dummies Questions & Answers

Hello

I've got a certain no. of files in a directory whose names I'm reading and redirecting into a temporary text file using the command below:

Code:

ls -l | grep ^- | awk '{print $9}'

However, whenever the file names contain spaces the above command considers only the part of the file name up to the first space. So a file called 'file name.txt' becomes 'file'

I'm sure that with the command I'm using, this is normal. However is there an alternate command that reads the entire file name irrespective of the file name having spaces?

Thanks a lot

Tony

Code:

ls -l | awk '/^-/{print substr($0, index($0,$9))}'

Code:

ls -1

This will work without the grep:

Code:

find . -mindepth 1 -maxdepth 1 -type f

Thanks a lot in2nix4life
This works the best for me since ls -l on its own returns too much info. where as I want just the file name.

The find command appends unwanted info. as well.

I however do have another subsequent command that ignores filenames with spaces. Basically, I copy the file names present into a temporary text file using in2nix4life's command above in the following way:

Code:

ls -l | awk '/^-/{print substr($0, index($0,$9))}' > LIST_FILES.txt

Now I need to count the number of lines in each file whose names are in this temporary text file which I'm doing using:

Code:

wc -l file name with blanks.txt| awk '{print $1}'

Unfortunately here its looking for different files called file, name, is & blank and not one file as it should be. I thus get:

Code:

wc: file: No file found
wc: name: No file found
wc: with: No file found
wc: blanks.txt: No file found

I guess there is a way to use the wc command so that it considers file names with spaces.

Can anyone please help me out?

Many thanks

Tony

Try:

Code:

wc -l "file name with blanks.txt"

File names with spaces need to be quoted, otherwise the shell will use the spaces to split the name into 4 different parameters..