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Typeset builtin error

 
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# 1  
Old 07-16-2014
Typeset builtin error
I'm attempting to emulate another users .zshrc file. However, I'm sort of confused on what exactly the -g argument does for the typeset builtin. Here's what he has in his .zshrc file:

Code:
typeset -ga sources
sources+="$ZSH_CONFIG/environment.zsh"
sources+="$ZSH_CONFIG/options.zsh"
sources+="$ZSH_CONFIG/prompt.zsh"
sources+="$ZSH_CONFIG/functions.zsh"
sources+="$ZSH_CONFIG/aliases.zsh"

Note: I've figured out that typeset is now deprecated and is now replaced with the declare builtin.

Also I've tried something similar in another shell script, however the script returns with the following errors:

Code:
declare -g folders

folders +="$HOME/Dropbox"
folders +="$HOME/Desktop"
folders +="$HOME/Downloads"

Output:

Code:
./.new.zsh: line 1: declare: -g: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
./.new.zsh: line 3: folders: command not found
./.new.zsh: line 4: folders: command not found
./.new.zsh: line 5: folders: command not found

Any idea what the -g argument is for? And why is it giving me an error when I attempt to run the script (not the .zshrc file) in terminal?
Code:
  1 declare -g folders
  2
  3 folders +="$HOME/Dropbox"
 folders +="$HOME/Desktop"
  folders +="$HOME/Downloads"

Code:
./.new.zsh: line 1: declare: -g: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
./.new.zsh: line 3: folders: command not found
./.new.zsh: line 4: folders: command not found
./.new.zsh: line 5: folders: command not found

Any idea what the -g argument is for? And why is it giving me an error when I attempt to run the script (not the .zshrc file) in terminal?
Moderator's Comments:
Mod Comment Please use CODE tags (rather than ICODE tags) when marking multi-line sample input, output, and code.
Last edited by Don Cragun; 07-16-2014 at 09:31 PM.. Reason: Add missing CODE tags and change ICODE tags to CODE tags.
# 2  
Old 07-16-2014
Very simply, the -g option is not recognized as a valid option for the typeset command in the shell you're using; so it gives you an error.

What does the man page for the shell that was used to interpret the script that was successfully using typeset -g say the -g option is supposed to do?

Are you using the same shell on the same system where typeset -g was used by the other user? What shell are you using? What OS are you using?

Why is it important for you to copy someone else's code if you don't know what it is trying to do?
This User Gave Thanks to Don Cragun For This Post:
brandontdr
# 3  
Old 07-16-2014
Quote:
Originally Posted by Don Cragun
Very simply, the -g option is not recognized as a valid option for the typeset command in the shell you're using; so it gives you an error.

What does the man page for the shell that was used to interpret the script that was successfully using typeset -g say the -g option is supposed to do?

Are you using the same shell on the same system where typeset -g was used by the other user? What shell are you using? What OS are you using?

Why is it important for you to copy someone else's code if you don't know what it is trying to do?

I am currently running zsh on OSX.

To answer your second question, I have searched the man pages for a solution, as a result, the shell returns, "no manual entry for typeset". The holds true for csh as well.

In brief, my overall goal here is to learn to read and use code from other programmers, perhaps make it better and apply it to something arbitrary.
# 4  
Old 07-17-2014
Quote:
Originally Posted by brandontdr
To answer your second question, I have searched the man pages for a solution, as a result, the shell returns, "no manual entry for typeset". The holds true for csh as well.
It happens that the man pages are not installed. If you do not have root access you cannot even install them. Fortunately there is the internet nowadays and most (practically all) man pages can be searched for and found on the net too. I have tried the obvious words "man zsh typeset" on google and up came (from this page, the first hit:

Quote:
The -g (global) flag is treated specially: it means that any resulting parameter will not be restricted to local scope. Note that this does not necessarily mean that the parameter will be global, as the flag will apply to any existing parameter (even if unset) from an enclosing function. This flag does not affect the parameter after creation, hence it has no effect when listing existing parameters, nor does the flag +g have any effect except in combination with -m (see below).
I suppose you are eager to do the rest of the searching (and reading) yourself. Happy programming.

bakunin
# 5  
Old 07-17-2014
Note also that there is a HUGE difference between the commands:
Code:
sources+="$ZSH_CONFIG/environment.zsh"

and:
Code:
folders +="$HOME/Dropbox"

That additional space completely changes what zsh does. The first command (with no space) adds the expansion of $ZSH_CONFIG/environment.zsh to the array named sources.

The second command (with a space) runs the command folders with the operand +="$HOME/Dropbox".
 
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