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Passing value in awk

 
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# 1  
Old 07-11-2014
Passing value in awk
Hi,

I want to pass value of the variable i which is the radius in the following command in bash script:
Code:
awk '{r=sqrt($2^2+$3^2+$4^2); if(r<=$i) print r }' input.txt

It ignores $i in if command and print the whole range. I tried to replace $i with 6 and it worked. Would some one help me please? Thank you.
Last edited by Franklin52; 07-12-2014 at 03:48 PM.. Reason: Please use code tags
# 2  
Old 07-11-2014
Use awk -v option for variable assignment and use that variable instead:
Code:
awk -v I="$i" '{r=sqrt($2^2+$3^2+$4^2); if(r<=I) print r }' input.txt

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