UNIX for Dummies Questions & Answers

Hi,

I am reading a particular date from a file using below command

Code:

WFLWDATE=$(sed '2q;d' FileA.prm)

The echo command outputs the correct date in variable WFLWDATE

Now I want to subtract 5 minutes from this variable. I am on AIX and unable to get anything working as expected.

Can you please suggest?

- Vrushank Patel

---------- Post updated at 08:47 AM ---------- Previous update was at 08:38 AM ----------

On this forum I was provided the below code to get 5 minutes subtracted. But this subtracted is from system date. I want to subtract from a variable

Code:

$(perl -e 'use POSIX qw(strftime);print scalar(strftime "%Y-%m-%d-%H.%M.%S" , localtime(time - 300)), "\n";' )

-Thanks
Vrushank Patel

Check this thread in FAQ section: Date Arithmetic