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Count total image in directory

 
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# 1  
Old 06-20-2014
Count total image in directory
Dear all,

I have a directory consisted of files in .jpg, .jpeg etc..all of them are image

Code:
20140411030143_62811159403_92886.jpg    5/11/2014 15:01    197K
20140415024737_62811618747_116460.jpg    4/15/2014 14:47    17K
20140415031003_62811618747_109192.jpg    4/17/2014 15:10    17K
20140415051411_6282113867071_22290.jpg    4/15/2014 17:14    8.6K
20140415090029_628118504524_33578.jpg    4/15/2014 9:00    223K
20140415090218_628118504524_73689.jpg    4/19/2014 9:02    223K
20140415094439_62811636636_63535.jpeg    4/15/2014 9:44    128K

I need to count sum of files by date

expected output should be
Code:
4/15/14    4
4/17/14    1
4/19/14    1
5/11/14    1

thanks
Last edited by radius; 06-20-2014 at 10:12 AM..
# 2  
Old 06-20-2014
Thoughts?
What have you tried to do this?
# 3  
Old 06-20-2014
One possible approach...

Code:
$ cat sample40.txt
20140411030143_62811159403_92886.jpg    5/11/2014 15:01    197K
20140415024737_62811618747_116460.jpg    4/15/2014 14:47    17K
20140415031003_62811618747_109192.jpg    4/17/2014 15:10    17K
20140415051411_6282113867071_22290.jpg    4/15/2014 17:14    8.6K
20140415090029_628118504524_33578.jpg    4/15/2014 9:00    223K
20140415090218_628118504524_73689.jpg    4/19/2014 9:02    223K
20140415094439_62811636636_63535.jpeg    4/15/2014 9:44    128K

$ cat sample40.txt | cut -d" " -f5 | sort | uniq -c
      4 4/15/2014
      1 4/17/2014
      1 4/19/2014
      1 5/11/2014

# 4  
Old 06-21-2014
Code:
awk '{print $2}' file | sort -b | uniq -c | awk '{print $2,$1}'

# 5  
Old 06-21-2014
Code:
awk '{T[$2]++} END{for(i in T) print i, T[i]}' file

 
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