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Print Only File Name in Zip File With out Unzipping It

 
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# 1  
Old 04-08-2014
Print Only File Name in Zip File With out Unzipping It
How i print just only the file name in the zip file.

Code:
unzip -l AAC_20130930_v13.xml.zip
Archive:  AAC_20130930_v13.xml.zip
  Length     Date   Time    Name
 --------    ----   ----    ----
 62665745  11-19-13 10:43   AAC_20130930_v13.xml
 --------                   -------
 62665745                   1 file

The closest i got it is.

Code:
unzip -l AAC_20130930_v13.xml.zip | awk '{print $4}' | sed '/^$/d'
Name
----
AAC_20130930_v13.xml

Thank you.
# 2  
Old 04-08-2014
Check zipinfo.
# 3  
Old 04-08-2014
You could also try:
Code:
unzip -l AAC_20130930_v13.xml.zip | awk 'NR > 3 && NF == 4 {print $4}'

This User Gave Thanks to Don Cragun For This Post:
Ariean
 
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