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awk - if else condition

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# 1  
Old 03-25-2014
IBM awk - if else condition

Need help in awk command.

Need to check 4th column of a file, if it is CAR then awk should print as is and if 4th column is not present, awk should print BIKE

Input File content :

Out put will look like:


Please advise. Thanks !!!

Last edited by Scrutinizer; 03-25-2014 at 07:12 AM.. Reason: code tags
# 2  
Old 03-25-2014
What have you tried so far?
# 3  
Old 03-25-2014
awk -F "," '$4 != "CAR" {$4 = "BIKE"}1' OFS="," file

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# 4  
Old 03-26-2014
Thanks a lot. Could you please explain logic as well?
print is not used here then how come it is printing whole line? What if i want to print specific columns only?
# 5  
Old 03-26-2014

 $ awk -F , '!$4{$4="BIKE"}1' OFS="," file


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# 6  
Old 03-26-2014

Following may also help in same.

awk 'NR==3 || NR==4 {$(NF+1)="BIKE"} 1' OFS=","  file_name

Output will be as follows.


R. Singh
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# 7  
Old 03-26-2014
Originally Posted by vegasluxor
Thanks a lot. Could you please explain logic as well?
print is not used here then how come it is printing whole line? What if i want to print specific columns only?
  1. -F "," - use comma as the field separator
  2. $4 != "CAR" {$4 = "BIKE"} - if field 4 is not 'CAR' then set field 4 to BIKE (note that this will replace anything that isn't CAR, not just empty ones)
  3. 1 - always TRUE (which matches every input line and prints it, since that's the default action)
  4. OFS="," - use comma as the output field separator

EDIT: If you only want to print specific fields you could change (3) to (e.g.):
{print $1 OFS $4}

to just print fields 1 and 4.

Last edited by CarloM; 03-27-2014 at 07:48 AM..
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