Simple unit script


 
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# 1  
Old 03-03-2014
Error Simple unit script

Hello guys this is my first post in this forum. Since now ive been passive an ive only been looking for existing information. Now I could use specific help on a UNIX script i want to make that would:

1. Take 1-3 arguments.
2. Display the contents of its arguments, formatted as follows:
Separator line
Filename
Separator Line
File content
Separator line
3. Display an error message, in case the arguments are less than 1 or more than 3.

How can i do that? i'm so confused.SmilieSmilieSmilie
# 2  
Old 03-03-2014
Hello,

Could you please be more clear on your requirement. Please share input and expected output with use for same. Also please make sure you are using code tags as per forum rules for code and commands please.


Thanks,
R. Singh
# 3  
Old 03-03-2014
If you're writing your script in Bash shell, you can handle the arguments like this:

Code:
#!/bin/bash
#
#

# check command-line for correct usage
if [ $# -eq 0 ] || [ $# -gt 3 ]
then
    echo "Usage: ${0##*/} <arg1> <arg2> <arg3>"
    exit 1
fi

Each argument will be stored in it's own variable: $1, $2, $3.
# 4  
Old 03-03-2014
After checking the number of parameters. One way is with a here document:
Code:
for file in "$@"
do
cat << EOF
------------------------------------------
$file
------------------------------------------
$(cat "$file")
------------------------------------------
EOF
done

or

Code:
for file in "$@"
do
  printf "%s\n" "------------------------------------------"
  printf "%s\n" "$file"
  printf "%s\n" "------------------------------------------"
  cat "$file"
  printf "%s\n" "------------------------------------------"
done

--
@in2nix4life : that code will work with any POSIX shell, not just bash...
# 5  
Old 03-03-2014
in unix script code with commands like read and cp and chmod
# 6  
Old 03-03-2014
It is all shell script. Is this homework?
# 7  
Old 03-03-2014
yes it is and i've missed some classes and I dont know that basic stuff
 
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