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[Solved] Grep multiple files and display first match

 
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# 1  
Old 02-10-2014
[Solved] Grep multiple files and display first match
I have a need to grep a large number of files, but only display the first result from each file. I have tried to use grep, but am not limited to it. I can use perl and awk as well. Please help!
# 2  
Old 02-10-2014
Code:
awk 's != FILENAME && /pattern/{print; s=FILENAME}' file1 file2 ....

with gawk:
Code:
gawk '/pattern/{print; nextfile}' file1 file2 ....

# 3  
Old 02-10-2014
That works perfectly! Is there a way to make it display the file name as well as the first matched line?
# 4  
Old 02-10-2014
Quote:
Originally Posted by dbiggied
That works perfectly! Is there a way to make it display the file name as well as the first matched line?
Sure.
Code:
awk 's != FILENAME && /pattern/{print FILENAME; print; s=FILENAME}' file1 file2 ....

Or with gawk:
Code:
gawk '/pattern/{print FILENAME; print; nextfile}' file1 file2 ....

# 5  
Old 02-10-2014
Like this ?

Code:
$ grep -m 1 'pattern' file*

# 6  
Old 02-10-2014
Quote:
Originally Posted by Akshay Hegde
Like this ?

Code:
$ grep -m 1 'pattern' file*

Be aware that the -m option is not available on all systems.
# 7  
Old 02-10-2014
Quote:
Originally Posted by Franklin52
Sure.
Code:
awk 's != FILENAME && /pattern/{print FILENAME; print; s=FILENAME}' file1 file2 ....

Or with gawk:
Code:
gawk '/pattern/{print FILENAME; print; nextfile}' file1 file2 ....

How would I modify this to place both the name of the file and the matched line on the same line in the output? perhaps separated by a colon or something?




Quote:
Originally Posted by Franklin52
Be aware that the -m option is not available on all systems.
My system does not have the -m option.
 
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