[Solved] Help -file archival

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# 1  
Old 02-05-2014
Question [Solved] Help -file archival

Hi All,
I have a scenario to append all the CSV files with date while moving from one directory to another directory .

Source DIR - A

files (can be more files, not sure about file names , but csv format )

Target Dir - B

I want my file names as

Where $date- today's date

Last edited by bartus11; 02-05-2014 at 04:23 PM.. Reason: Please use [code][/code] tags.
# 2  
Old 02-05-2014
DT=$( date +"%Y%m%d" )

for file in DIR_A/*.csv
        echo mv "$file" "DIR_B/${fname%.csv}${DT}.csv"

Remove echo if output looks good. Replace DIR_A, DIR_B with actual absolute paths.
This User Gave Thanks to Yoda For This Post:
# 3  
Old 02-05-2014
a sample script below will go through all csv files in the current directory and rename files with current date:
today=$(date '+%Y%m%d');
for fname in *.csv; do
        echo $fname $new_name;
        # mv $fname $new_name;

here are csv files in my directory:
$ ls *csv

and here is result:
aaa.csv aaa.20140205.csv
bbb.csv bbb.20140205.csv

if you see that results fit you then uncomment the mv statement below echo and it will do the job.

If you want to place resulting files in another directory just add the archival directory to the script

and change the new_name forming to reflect that:

This User Gave Thanks to migurus For This Post:
# 4  
Old 02-05-2014
One nice archiving method is to zip the files and directories. HXTT JDBC can read them from zip like a table, selecting zip files and zipped files by wild card to form a table. The shrink great, too, and might come out faster, as CPUs are way faster than disks.
# 5  
Old 02-06-2014
Hi All ,
Thanks For your reply .

Now if i have multiple file with different extn

How to i see the output as

Last edited by AspiringD; 02-06-2014 at 01:21 PM..
# 6  
Old 02-06-2014
for file in *.txt *.csv *.xml

# 7  
Old 02-06-2014
Hi Yoda , the file can be of any extension
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