UNIX for Dummies Questions & Answers

My problem in brief is that I execute a script from another script and I can not pick up the return code from that script, or otherwise I am not returning from that script. I have an echo in the executed script and we get a response code of 0 and exit that script with the return code. I then try to assign the return code to a variable SCHEDULER_EXIT in the executing script and echo that to a file. I never get to the echo, so the script ends on the assign of the return code to the variable SCHEDULER_EXIT, or it never gets there.

Code:

exec /udd026/SAS_Progs/IVEREX62.sh $SCHEDULER_ARGS >> /udd001/app/TWS/logs/TWS_MRun.log 
 SCHEDULER_EXIT= $?
 echo IVEREX62 $STAB `date`  has ended scheduler exit ${SCHEDULER_EXIT} >> /udd001/app/TWS/logs/TWS_MRun.log

any ideas?

Hi, you are using exec, so the shell executing /udd026/SAS_Progs/IVEREX62.sh will replace the parent script's shell, without creating a new process. So this code:

Code:

SCHEDULER_EXIT= $?
 echo IVEREX62 $STAB `date`  has ended scheduler exit ${SCHEDULER_EXIT} >> /udd001/app/TWS/logs/TWS_MRun.log

will never get executed. Try leaving out exec



--
BTW: there should not be any spaces around the assignment operator (=):

Code:

SCHEDULER_EXIT=$?