UNIX for Dummies Questions & Answers

Given the following loop:

foreach id (DB4 GH4 CD4)

and the previously defined variables:

DB4sf DB4sfk DB4pp
GH4sf GH4sfk GH4pp
CD4sf CD4sfk CD4pp

how do i echo all of these variables using a one line command in the for loop. If it was a script, and assuming the previously mentioned variables, it would look like this if it worked.

#! /bin/csh
foreach id (DB4 GH4 CD4)

echo $idsf $idsfk $idpp
end

exit 0

Try This

#! /bin/csh
foreach id (DB4 GH4 CD4)

echo ${id}sf ${id}sfk ${id}pp
end

exit 0

Thanks ,
Ashok

Doing this displays:
DB4sf DB4sfk DB4pp, then likewise for each remaining word. Anyone else have an idea? I know the variable has been set, because if i just echo the actual variable name i get the value.

Can you give an examples of the output you want ?

Yup, the output will be a string then some numerical values, such as


DB4 4 0 1 4

The first field is a site id, the next four fields are just that numbers.

So the value is already set in a previous portion of my script, but since there are over 30 sites I have to do this for, I am trying to display it using one line, hence the:

echo $id $idsf $idsfk $idpp

DB4sf has a value assinged to it, i just need to display it using a variable. Using the curly braces, just displays DB4sf rather than the numerical value. Hope this helps, thanks for looking at this for me.

I think that csh has eval, so try this:

#! /bin/csh
foreach id (DB4 GH4 CD4)

eval echo \$${id}sf \$${id}sfk \$${id}pp
end

exit 0

hey that worked awesome, thanks a lot.