UNIX for Dummies Questions & Answers

I know how to search for a pattern/regular expression in many files that I have in a directory. For example, by doing this:

Code:

grep -Ril "News/U.S." .

I can find which files contain the pattern "News/U.S." in a directory.

I am unable to accomplish about how to extend this code so that it can search for 3 consecutive lines in the files which contain the above pattern. The code should only output file names which contain three consecutive times the above pattern, and disregard less than 2 or 4 or greater.

I mean:

Code:

News/U.S.
News/U.S.
News/U.S.

As you can see News/U.S. appears 3 times consecutively in newlines. I want to output those file names which contain the above pattern. I am using Linux with BASH.

I don't think you can do this with grep. You may want to try this awk that works with the sample you posted. For different input it may need to be modified.

Code:

awk '/News\/U.S./ {CNT++; next} CNT==3 {print FILENAME} {CNT=0}' file