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Search and replace the last field


 
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# 1  
Search and replace the last field

Hi All,

Seeking for your assistance on how to search and replace the last field/column. please see sample below:

Code:
inputfile1.csv
="8923523434",="543623534"="afd23535623",="100"="200"
="8923523431",="543623536"="afd23535626",="101"="201"
="8923523432",="543623538"="afd23535622",="104"="202"

sample expected output
Code:
inputfile1.csv
="8923523434",="543623534"="afd23535623",="100200"
="8923523431",="543623536"="afd23535626",="101201"
="8923523432",="543623538"="afd23535622",="104202"

it will replace the "=" in the last field of the data.

what i did was:

Code:
awk3=`awk -F "," '{print $4}'  inputfile1.csv | sed -e 's/="//g' -e s'/"//g'`

while IFS=, read a b c d; do
d=$(echo "${awk3}; $d)
echo "$a,$b,$c,$d"
done < inputfile1.csv > final.csv

the problem is it will print the whole records in $d i think due to awk. i don't know else what to do please help.

Please advise,

Thanks,
# 2  
Hello,

Could you please try as follows.



Code:
$  awk -vs1="=" -F"=" '{print $1s1$2s1$3s1$4s1$5$6}' file_name | sed 's/\"\"//g'
="8923523434",="543623534"="afd23535623",="100200"
="8923523431",="543623536"="afd23535626",="101201"
="8923523432",="543623538"="afd23535622",="104202"


Thanks,
R. Singh
# 3  
... or like
Code:
awk -F, 'sub (/"="/, "", $NF)' OFS=, file
="8923523434",="543623534"="afd23535623",="100200"
="8923523431",="543623536"="afd23535626",="101201"
="8923523432",="543623538"="afd23535622",="104202"

# 4  
Code:
while IFS=, read a b c
do
        echo "${a},${b},${c/\"=\"/}"
done < inputfile.csv

 

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