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If (! -z $file || $status != 0 ) ... what its mean

 
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# 1  
Old 12-03-2013
If (! -z $file || $status != 0 ) ... what its mean
hi can anybody help ..

Code:
if (! -z  $file || $status != 0 )

... what its mean

Moderator's Comments:
Mod Comment Use code tags, see PM.
Last edited by zaxxon; 12-03-2013 at 09:05 AM..
# 2  
Old 12-03-2013
That depends on the environment that you are working in. Let's assume it's a bash shell, it comes close to a test of a file size being not zero and a status not being 0. But were it bash, the right syntax would be either
Code:
if [ ! -z "$file" ] || [ "$status" != 0 ]

or
Code:
if [ ! -z "$file" -o "$status" != 0 ]

# 3  
Old 12-03-2013
Assuming that is the csh shell, it means

if
[ the variable $file is not empty ]
or
[ the variable $status is not equal to zero ]



It helps to give context to your questions - assuming you want a decent answer.
So, it this csh shell code?
This User Gave Thanks to jim mcnamara For This Post:
Madhu Siddula
# 4  
Old 12-03-2013
Presumably.
This User Gave Thanks to CarloM For This Post:
jim mcnamara
# 5  
Old 12-03-2013
As you can tell we are all guessing....
# 6  
Old 12-03-2013
You are double posting questions, which can be quite annoying as you will get a variety of different answers in different threads, but the discussion will wander about depending who answers what where and we will spend double time trying to help you - and we're all doing this for free.


As on the other thread directed to by CarloM I would suggest:-

Quote:
Have a read of the manual pages for test
Code:
man test

There are all sorts of options you can use in deciding which chunk of code to process next.


I hope that this helps more than me just giving you a one-line answer.



Robin
Liverpool/Blackburn
UK
# 7  
Old 12-04-2013
yes it is cshell code .. Thanks for u r post

---------- Post updated at 11:48 PM ---------- Previous update was at 11:43 PM ----------

yes, it is Cshell script code only
 
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