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Condition based on Timestamp (Date/Time based) from logfile (Epoch seconds)

 
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# 1  
Old 11-22-2013
Condition based on Timestamp (Date/Time based) from logfile (Epoch seconds)
Below is the sample logfile:

Userids Date Time
acb Checkout time: 2013-11-20 17:00
axy Checkout time: 2013-11-22 12:00
der Checkout time: 2013-11-17 17:00
xyz Checkout time: 2013-11-19 16:00
ddd Checkout time: 2013-11-21 16:00
aaa Checkout time: 2013-11-18 17:00
yyy Checkout time: 2013-11-22 12:00


Objective: I like to sort out userid who have checked out the application for more than 24hours.

Let's assume I have cronjob scheduled to run at 17:00 on Nov 22nd 2013, If Checkout time > 24hrs then, expected results should look like below:

acb User Checked out license for more than 2 days
der User Checked out license for more than 5 days
xyz User Checked out license for more than 2 days
ddd User Checked out license for more than 1 days
aaa User Checked out license for more than 4 days


I was trying to covert $4 & $5 to epoch seconds using (date +%s -d "$3 $4") and subtract this from (date +%s) if difference is > 24hrs (86400Sec) then print user id. But lacking my knowledge to get variable right.

Thanks for your help
# 2  
Old 11-22-2013
What are $4 and $5? That looks like awk, not shell. It is useful to know what language you are expecting us to program in Smilie
# 3  
Old 11-22-2013
Yes, I am looking to acheive this in "awk"
# 4  
Old 11-22-2013
You can feed those strings into GNU awk's or mawk's mktime function:

Code:
sub(/:/, " ", $4); TS=mktime($3 " " $4 " 00" );

# 5  
Old 11-22-2013
I executed following awk command to print Variable “TS”
awk ' {sub(/:/, " ", $5); TS=mktime($4 " " $5 " 00" ); print TS}' logfile

Output:
1323644400
1323453600
1323903600
1323727200
1323554400
1323817200
1323453600
-1

I have question these seconds are not match if I output epoch second using date +%s -d "2013-11-20 17:00 " it's giving me 1384988400 seconds which not matching with 1323644400 1st lineof output.
And Why there -1 at the end of program.

Is there way to use date i.e date +%s -d "2013-11-20 17:00 .

Please suggest I am not routine Linux user

Thanks!
# 6  
Old 11-22-2013
Huh, that is a large difference. Check what the $4 " " $5 " 00" actually becomes? awk's mktime() expects "YYYY MM DD HH MM SS"

[edit] Add a sub(/-/, " ", $4); statement to the program, the dashes are probably confusing it.

Running GNU date 9,000 times is not going to be very efficient at all. if you have mktime() in awk it's best to use it.
Last edited by Corona688; 11-22-2013 at 03:51 PM..
# 7  
Old 11-22-2013
Removed “-“ from date format
excecuted cmd: awk ' {sub(/:/, " ", $5);sub(/-/, " ", $4); TS=mktime($4 " " $5 " 00" ); print TS}' timestamp.txt

Output:
1381528800
1381338000
1381788000
1381611600
1381438800
1381701600
1381338000
-1

Still the difference is very large.

I am not expecting logfile more than 150lines (50 to 150 max), That's why I was looking into GNU date which is easy for epoch conversion.
 
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