UNIX for Dummies Questions & Answers

Hi ,

i will be getting 24 files for one day with a formate like 20131028_01 - 20131028_24 kind of ,i am trying to write a shell script to count the number of files and if the count is not equal to 24 print the missing files names

Code:

 for A in `seq 0 23`; do ls *20131024_`printf "%02d" $A`*; done

this gives me a complete list but i just want the missing files any help would be thank full

Instead of ls, use [ (aka test) to check for the existence of the file. If the test fails, then print the name.

Regards,
Alister

can you show me the usage

Read man test or check your shell's manual page (ksh and bash, for example, have a builtin version that they document).

Regards,
Alister