Lists in awk

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# 1  
Old 09-19-2013
Lists in awk

Hi togehter!

I would like to write an awk script which prints the first column divided by the sum of the second column:

So if this is my list

1 2
2 1
3 1
4 1

it should print a list like this:


My idea was to use END like this:

 awk '{sum+=$2;} END {print $1/sum}'

But it doesnt work... can someone help me?

# 2  
Old 09-19-2013
$ awk 'NR==FNR{a+=$2;next}{print $1"/"a}' file file

This User Gave Thanks to pamu For This Post:
# 3  
Old 09-19-2013
awk '{sum+=$2;a[++i]=$1} END{for (i in a) {print a[i]"/"sum}}'  infile

This User Gave Thanks to krishmaths For This Post:
# 4  
Old 09-19-2013
Originally Posted by krishmaths
awk '{sum+=$2;a[++i]=$1} END{for (i in a) {print a[i]"/"sum}}'  infile

The for-in-loop should not be used. The OP wants to preserve the order of the list, buti in a is not guaranteed to preserve order.
awk '{sum+=$2; a[NR]=$1} END{for (i=1; i<=NR; i++) {print a[i]"/"sum}}'  infile


Last edited by alister; 09-19-2013 at 12:21 PM..
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