UNIX for Dummies Questions & Answers

Hey,

My access.log for one application is not rolled over.

I would like to get users count.

Right now I am doing

Code:

cat logon.list | grep 2013-09-11| |grep Succeeded | wc -l

Since the file doesnt rotate out I have to grep for new date/
I tried to specify DATE=date "+DATE: %Y-%m-%d" in a script but grep string isnt correctly done.

How to get awk to pick the latest data and grep and wc-l out latest user logons?

Thanks,

You are setting DATE to the string "date" (and probably getting an error message something like +DATE: %Y-%m-%d: not found).

Assuming that "Succeeded" follows the date in your log file, try:

Code:

DATE=$(date "+DATE: %Y-%m-%d")
grep -c "$DATE.*Succeeded" logon.list

Since you didn't show us any sample input nor expected output, I have no way to verify that this will do what you want. Note that the greps that are working for you above are not looking for DATE: before the 2013-09-11 that the expansion of your DATE variable will include.

So the objective is not have to update the "date" - the command should use the system date to provide total count of users who "succeeded" in their logon attempt

Any other ideas, anyone?

---------- Post updated at 11:32 AM ---------- Previous update was at 11:20 AM ----------

Ended up using date=`date '+%Y-%m-%d'` as the variable and get the total count now.
Thanks for contributing!