I am new to shell script.I need your help to write a shell script.
I need to write a shell script to extract data from a .csv file where columns are ',' separated.
The file has 7 columns having values say column 1,column 2.....column 7 as below along with their values.
Name, Address, Account, Date, Dateofbirth, city, country.
Code:
Alpha, 146, 0012365, 12/13/1982, 12/13/1982, delhi, india
Now i want to write a script to first check if the file name.csv exists at /home/home1.
If the file exists i want to display column 2,column 4,column 5,column 6 and column 7 header along with their values if there are any values in it.
Output should be like below:
Code:
Address :146
date :12/13/1982
dateofbirth :12/13/1982
City :Delhi
Country :India
the above output should be send to mail abc@gmail.com
Last edited by Franklin52; 08-28-2013 at 03:23 AM..
Reason: Please use code tags
#!/bin/ksh
IFILE=/home/home1/name.csv
OFILE=/home/home1/name.csv.out
if [ -r $IFILE ] #Checks if file exists and readable
then
awk -F, '(NR==1){h2=$2;h4=$4;h5=$5;h6=$6;h7=$7;next} {print h2":"$2"\n"h4":"$4"\n"h5":"$5"\n"h6":"$6"\n"h7":"$7}' $IFILE > $OFILE
fi
cat $OFILE | mail -s "My data" abc@gmail.com
It gives syntax error as below:
^ syntax error in for all awk statements(as many times awk command is executed) and at the last write ^ backslash not last character of line.
---------- Post updated at 03:12 AM ---------- Previous update was at 03:04 AM ----------
One more thing..if there are more than 1 rows for all the columns,i need to displays all the rows in the output.Sorry for not clarifying in initial post.
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