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Invalid arithmetic operator

 
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# 1  
Old 08-11-2013
Invalid arithmetic operator
Hi experts,

I'm facing trouble with the below bash script, any help is appreciated
Code:
#!/usr/bin/bash
..
if (( "${date1}" > "${l_date1}" ))

then
echo "success"

else
echo "nothing"
fi

the variable date1 contains 08/06/2013 and l_date1 contains 10/08/2013

this small script to single out the error. Please advise.

Code:
 > 08/06/2013 ")syntax error: invalid arithmetic operator (error token is "

# 2  
Old 08-11-2013
Don't use parentheses; use [[ . . . ]] instead.
And, be aware that this will be a string compare, so 10/08/2013 is gt 09/08/2014...
This User Gave Thanks to RudiC For This Post:
parpaa
# 3  
Old 08-11-2013
Thank you rudi
that did it. Thank you

---------- Post updated at 11:44 PM ---------- Previous update was at 11:39 PM ----------

HTML Code:
if [[ ...]] && [[ ...]]
elif [[...]] && [[..]]
else "sometext"
Will this work?

Also is there any other way to deal with date comparison?
Last edited by parpaa; 08-11-2013 at 03:16 PM.. Reason: more info
# 4  
Old 08-11-2013
Have spaces around the [[ and ]], use ; then and fi, and then it should fly...
# 5  
Old 08-11-2013
Thanks again
One last question,

Is there any way to deal with date "comparison"??
since this will be a string compare;
# 6  
Old 08-11-2013
Convert to "seconds since epoch" or use YYYY/MM/DD format.
# 7  
Old 08-11-2013
thank you
Perfect, Thank you soooo very much SmilieSmilieSmilieSmilieSmilieSmilie
 
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