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Top Forums UNIX for Dummies Questions & Answers question?
# 1  
Old 11-19-2005

Is there any way to use sed and count the number of alphabetic characters in a sentence?
# 2  
Old 11-20-2005
Is this homework?
# 3  
Old 11-20-2005
try this,

not thoroughly tested,

# !/usr/bin/ksh

word="count of no of characters"

while :
if [ curr = `echo $word  | sed -e "s/$match//"` ] 2>/dev/null
cnt=$(($cnt + 1))
cnt=$(($cnt + 1))

echo "word count: $cnt"
exit 0

# 4  
Old 11-20-2005
echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c

# 5  
Old 11-21-2005
Originally Posted by vgersh99
echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c

the above cnt would include the terminating character also

count=$((`echo '123abc237R,6|' | sed 's/[^a-zA-Z]//g' | wc -c` - 1))
echo $count


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