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Print rows with substring in column

 
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# 1  
Old 07-23-2013
Print rows with substring in column
Hi I want to print all rows where there is the alphabet N in the 6th column as a substring.

Here is what i tried and not working.Please help !


Code:
awk '  {    if ( $6 == *"N"* )  print $0} '

awk '  {    if ( "${6}" == *N* )  print $0} '

 awk '  {    if( grep -q N <<<$6) print $0} '

# 2  
Old 07-23-2013
Code:
awk '$6 ~ /N/' file

 
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