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Help in script to check file name with todays date

 
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# 1  
Old 07-11-2013
Help in script to check file name with todays date
I am trying to include a snippet in my script to check if the file created is having today's date.

eg: File name is : ABC.YYYYMMDD-nnn.log

The script should check if 'YYYYMMDD' in the above file name matches with today's date.
Can you please help me in achieving this.
Thanks in advance!!
# 2  
Old 07-11-2013
Code:
ls "ABC.$( date +%Y%m%d )-nnn.log"

# 3  
Old 07-12-2013
Thanks for the reply, but I need to check if the 'YYYYMMDD' field in the filename equals to todays date.
I can take today's date into a variable and do a comparison, but how to compare it to only a part of the file name ?Smilie
Ex:File name: 'ABC.YYYYMMDD-nnn.log'
# 4  
Old 07-12-2013
Use parameter substitution to extract specific part of file name and then compare.

Assuming file name is stored in variable: file
Code:
f_dt="${file#*.}"
f_dt="${f_dt%-*}"

s_dt="$( date +%Y%m%d )"

if [ "$f_dt" = "$s_dt" ]
then
        # Action if true
else
        # Action if false
fi

# 5  
Old 10-24-2013
Hi Yoda, am learning shell script , may u please let me know how this command is working what does mean of # with variable and % in variable.

"${file#*.}"
# 6  
Old 10-24-2013
# - Delete the shortest part of a pattern (dot) that matches in the beginning of variable $file.

Code:
file=ABC.YYYYMMDD-nnn.log
$ echo ${file#*.}
YYYYMMDD-nnn.log

% - Delete the shortest part of a pattern (-) that matches at the end part of variable $file.
Code:
file=ABC.YYYYMMDD-nnn.log
$ echo ${file%-*}
ABC.YYYYMMDD

 
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