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Capture Multiple Lines Into Variable As Of Standard Output

 
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# 1  
Old 05-31-2013
Capture Multiple Lines Into Variable As Of Standard Output
Hello All,
I have the below script and output.

Code:
cat test.sh
#!/bin/bash -x
logit()
{
 echo "[${USER}][`date`] - ${*}" > ${LOG_FILE}
}
LOG_FILE=/home/infrmtca/bin/findtest.log

VAR=`find . -type f -name "*sql"`
logit $VAR

Output:
Code:
 cat /home/infrmtca/bin/findtest.log
[infrmtca][Fri May 31 15:02:59 EDT 2013] - ./dwh_StageDataValidation.sql ./dwh_MoveDataFromStageToWarehouse.sql

Here as you the output of find command is printed in same line in log file. Instead i would like it to be printed as a list as of standard output when you execute the find command like below. please help.

Code:
find . -type f -name "*sql"
./dwh_StageDataValidation.sql
./dwh_MoveDataFromStageToWarehouse.sql

Expected Output:
Code:
[infrmtca][Fri May 31 15:02:59 EDT 2013] - 
dwh_StageDataValidation.sql
dwh_MoveDataFromStageToWarehouse.sql

# 2  
Old 05-31-2013
Using GNU find:
Code:
echo -e "[${USER}][$(date)] -\n$(find . -type f -name "*sql" -printf "\t%f\n")"

This User Gave Thanks to Yoda For This Post:
Ariean
# 3  
Old 05-31-2013
I find it amusing that you use the -printf option of find, yet feel the need to use echo -e to use \n, rather than use printf!
This User Gave Thanks to Scott For This Post:
Yoda
# 4  
Old 05-31-2013
I modified my script as per your inputs but still not getting desired output.
Code:
#!/bin/bash -x
logit()
{
 echo "[${USER}][`date`] -\n${*}" > ${LOG_FILE}
}
LOG_FILE=/home/infrmtca/bin/findtest.log

VAR=`find . -type f -name "*sql" -printf "\t%f\n"`
logit $VAR

Output:
Code:
[infrmtca][Fri May 31 15:36:40 EDT 2013] -\ndwh_StageDataValidation.sql dwh_MoveDataFromStageToWarehouse.sql

# 5  
Old 05-31-2013
Quote:
Originally Posted by Ariean
Code:
VAR=`find . -type f -name "*sql"`
logit $VAR

You need to double quote $VAR when you call logit, otherwise the newlines are lost to word splitting.

Regards,
Alister
This User Gave Thanks to alister For This Post:
MadeInGermany
# 6  
Old 05-31-2013
@Scott, I thought of using printf instead of echo.

But using format specifiers with printf would make the code appear cryptic, hence used echo instead.
# 7  
Old 05-31-2013
The echo in logit needs an -e option in order to interpret the \n correctly.
 
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