Compare the content of a variable with a string


 
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# 1  
Old 10-31-2005
Compare the content of a variable with a string

Hello all:

I'm new in Unix and here and I'am spanish so my english isn't so good to explain my doubt. Here it is.

Very urgent:

I need to compare the value of a variable with a string.
Example is this.

Imagine that the variable x1 contains the path and a file text and I need to compare this with a string to put later with a echo a message

Could you help me?

I need to get only the name of the file without the path and I don't know how to do this. Something like this?

For_prp contains the path: C:\Program_Files\example\A1\prueba.txt and I need to compare with "prueba". Is like this?

if [ `grep -l '*prueba' ${For_prp}` ];
then
echo "The file${For_prp} is form the module of Pruebas"

Than you
# 2  
Old 10-31-2005
So you want to check that the file path contains a certain string?

Generally, you can do this by checking the exit status of the grep...

For example:

Code:
$ ( echo "${For_prp}" | grep "preuba.txt" >/dev/null 2>&1) && echo "Yes" || echo "No"
No
$ ( echo "${For_prp}" | grep "prueba.txt" >/dev/null 2>&1) && echo "Yes" || echo "No"
Yes

We can show this in an easier to understand form too:

Code:
echo "${For_prp}" | grep "prueba.txt" >/dev/null 2>&1
if [ "$?" -eq "0" ]; then 
  echo "Yes"
else
  echo "No"
fi

Cheers
ZB
# 3  
Old 11-01-2005
Than you very much

thanks a lot
 
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