Finding the files and count then


 
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# 1  
Finding the files and count then

Hi i was trying to find the files which are not older than one day and copy them to other location . but i need to count the number of files and the copy them if the count is matches my number

Code:
A=`find $SOURCE/* -type f -mtime -1 `

in the code above i need to count the number of file A has (it should be 6) .if the number macthes i would copy else i would exit. i thought of usnig some thing like if count =6 then copy kind of thing. Any ideas would be appericated
# 2  
Try assigning an array and then testing its element count:
Code:
$ A=( $(ls) )
$ echo "${#A[*]}"
16

# 3  
RudiC, I think that approach will cause discrepancies in count if there are file names with blank space. Isn't that right?
# 4  
Hi i tried this,but didnt work


Code:
#!/bin/bash
A=`find /path/to/files/* -type f -mtime -1 `
if [ "${#A[*]}" -eq 6 ]
then
something here
fi

# 5  
Quote:
Originally Posted by Yoda
RudiC, I think that approach will cause discrepancies in count if there are file names with blank space. Isn't that right?
Yes, filenames with spaces will cause trouble. Try this:
Code:
$ IFS=$'\n' A=( $(ls -1) )
$ echo ${#A[*]}
13

Quote:
Originally Posted by vikatakavi
Hi i tried this,but didnt work
. . .
It can't, because you didn't do what I proposed. You did not assign an array.
# 6  
Hi Rudic ,

Code:
#!/bin/bash
A=`find /path/to/files/* -type f -mtime -15 `
IFS=$'\n' A=( $(ls -1) )
echo ${#A[*]}

it returned 63 ,i am not sure for what that value is for

Last edited by vikatakavi; 05-23-2013 at 06:20 PM..
# 7  
Try assigning to an array (but take care of spaces in filenames!):
Code:
A=( $(find /path/to/files/* -type f -mtime -15) )

 

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