UNIX for Dummies Questions & Answers

Hi.

I have scheduled back to back 3 cron jobs in different files..

Code:

*/10 * * * * cal

Code:

 10 10 * * * uptime

Code:

 10 * * * 1,2 date

This what i have doe.. Now i want to list all these jobs. I have tried

Code:

 jobs -l

but it gives the recently scheduled job i,e

Code:

10 * * * 1,2 date

. How can print all those 3 jobs in an order..
That is i need output like below..

Code:

root@localhost $] command

Code:

*/10 * * * * cal

Code:

 10 10 * * * uptime

Code:

 10 * * * 1,2 date

These commands help you

Code:

crontab -l
man crontab

Already I have used

Code:

crontab -l

. .I got the job which was recently scheduled. . What about the remaining??

First of all tell us what do you mean by "different files"?

3 kind of files. .

I'd be surprised if jobs -l yielded a crontab entry like you posted. jobs will list jobs in the shell's process group, which will not normally have cron jobs in it.
If you want running processes listed, you may be lucky if they belong to a special user (e.g. "cron") when running ps. You can list or grep your system log to find out which jobs have been started when by cron.
The output you posted is merely the result of a crontab -l, nothing else, nothing to do with "recently scheduled".