How do I count how many times a specific word appear in a file (ksh)?


 
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# 1  
How do I count how many times a specific word appear in a file (ksh)?

Hi
Please can you help how do I count the number of specific characters or words that appear in a file?
# 2  
Can you post your input file format? That might simplify the task a bit
# 3  
Hi, is this what you need?
Code:
X=STRING_TO_SEARCH
cat file.txt |sed "s/$X/\n$X\n/g"|grep -c "$X"

# 4  
How do I count how many times a specific word appear in a file (ksh)?

did not work, because it return 108, but i this case there were only 2 lines with a different character
# 5  
Can you post a sample input and desired output?
# 6  
How do I count how many times a specific word appear in a file (ksh)?

I have a txt file with this:

Code:
./INV2143244.41006.ps
./INV18182.41006.ps
./INV18182.41008.ps
./INV75508.41006.ps
./INV2147827.41006.ps
./INV1803373.41006.ps
./INV2148121.41006.ps
./INV2151863.41006.ps
./INV43895.41006.ps
./INV446896.41006.ps
./INV78838.41008.ps

And as you can see from the above there are some line with digit 8 just before
Code:
.ps

So I want to count only those lines with digit 8 like
Code:
./INV78838.41008.ps

# 7  
If I understand your requirement correctly, then below command will do:
Code:
grep -c "8\.ps" file

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