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How to compare to values returned from sql in shell scripting?

 
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# 1  
Old 05-07-2013
How to compare to values returned from sql in shell scripting?
hey i am using this code to connect to sql , store the value in variable and then
compare it with another variable after some time by executing the same query
but the desired result is not coming


Code:
#!/bin/bash
val=$(sqlplus -s rte/rted2@rel76d2 <<ENDOFSQL
set heading off
set feedback off
SELECT MAX(STAT_ID) FROM CVT_STATS;
exit
ENDOFSQL)

nohup ./cvt -f MediationSources.xml &

sleep 60

value=$(sqlplus -s rte/rted2@rel76d2 <<ENDOFSQL
set heading off
set feedback off
SELECT MAX(STAT_ID) FROM CVT_STATS;
exit
ENDOFSQL)

if ["$val" =="$value"] ; then
  echo "FAIL"
else
  echo "PASS"
fi
~

Last edited by Scott; 05-07-2013 at 09:02 AM.. Reason: Code tags; Moved thread - does not appear to be an AIX-specific problem
# 2  
Old 05-07-2013
check your if loop...
let us know the output of val and value.. Is it strig or numeric? looking at it i guess its numeric.. use -eq instead of ==

Code:
 
if [ $val == $value ] ; then

# 3  
Old 05-07-2013
but this is also not working .
whatever the value of stat_id , whether greater or equal to it is returning
pass.
# 4  
Old 05-07-2013
Quote:
Originally Posted by ramsavi
but this is also not working .
whatever the value of stat_id , whether greater or equal to it is returning
pass.
Have you tried -eq instead of == as suggested in my post?
# 5  
Old 05-07-2013
Perhaps you should start by fixing the syntax of this line:
Code:
if ["$val" =="$value"]

To
Code:
if [ "$val" = "$value" ]

# 6  
Old 05-07-2013
yes i have tried those
# 7  
Old 05-07-2013
Then you need to add some echo debug to see the values of $val and $value, because there looks to be nothing else wrong with the code. And post, please, the exact code you have used, because what you have posted has syntax errors.

Code:
val=$(...)
value=$(...)
...
echo "\"$val\""
echo "\"$value\""
...

 
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