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Help in this shell script


 
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# 1  
Old 10-05-2005
Help in this shell script

Hi ,
I am trying to do following.
Problem - " Take out today's day from date and then based on day echo some thing. But some how the control is not going in case switch"

Code - here is code

++++++++++++++++++++++++
DAY= date | cut -f 1 -d ' '
echo "$DAY---- is X"

case $DAY in
'Wed')
echo "Today is $DAY - day"
;;
*)
echo "Kya ho raha hai"
;;
esac


+++++++++++++++
So I checked that the cut command is returning me "Wed" with a new line character.
So out put of running above code is

=======
% sh dr.sh
Wed
---- is X
Kya ho raha hai
=======
So you can see extra newline character comin in play !!!!
So can any one help how to truncate all the extra spaces while using cut command ? ANd how can I maeke case run fine here?

thanks in advance
# 2  
Old 10-05-2005
This line:
DAY= date | cut -f 1 -d ' '
does not set the variable DAY to anything. It is basicly the same as:
date | cut -f 1 -d ' '

And then the next line just prints an empty $DAY variable.

You want something like:
DAY=`date | cut -f 1 -d ' '`

Next time please tell which shell you are using. Also which version of unix.
# 3  
Old 10-05-2005
Hi,
I agree I was making a mistake by putting 'space' between + and statement.
But still I am not able to assign the day to variable. I tried using excape character also i.e \' \' ' but no use.
Now my command looks like

DAY='date | cut -f 1 -d \' \''

I am using ksh. and on SUn SOlaris.

thanks
Himanshu
# 4  
Old 10-05-2005
Cut and paste my statement. The syntax must be exact.
` = back quote
' = single quote
" = double quote
all very different.
# 5  
Old 10-05-2005
Thanks it worked

Hi
thanks a lot for clearing up the thing. I got it. tht is " ` " (graveascent) to be used when to execute unix command in Shell script.

this thing worked

`date | cut -f 1 -d ' ' `

Thanks again a lot
 

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