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using cut to extract info

 
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# 1  
Old 10-03-2005
using cut to extract info
a simple question,

how can i use cut (after using grep) to extract the last four digits on a line.

so say i had a string http://blabla:9020, how would I extract the port??

-Fez
# 2  
Old 10-03-2005
how about awk?
Code:
grep 'stuff' file | awk 'BEGIN {FS=:} {print $2 }'

# 3  
Old 10-03-2005
Using CUT

echo 'http://blabla:9020' | cut -d: -f3

This is homework, isn't it?

Tony
tony3101
# 4  
Old 10-04-2005
Just sed

Code:
echo "http://www:9090" | sed -e "s/.*:\([0-9]\{4\}\)/\1/"

# 5  
Old 10-04-2005
By suggesting an alternate like sed or awk, if the OP is not doing homework, you help anyway. And you don't do somebody's homework. Smilie
 
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