UNIX for Dummies Questions & Answers

Hello all
I am very new to scripting and would like your help to accomplish this task.

I have to cd the adump directory every single day and manually run the following command when I receive an alert saying that audit files exceeded 10.000 files limit.

cd /opt/app/dcweblog/oracle/admin/PW4ARBY/adump
find . -name '*.aud*' | xargs rm

What I need is the step to implement to automate to run twice everyday
####################
vi maxrm_audfile.ksh
#!/bin/bash
find . -name '*.aud*' | xargs rm

####################

thanks in advance

You should do

find /absolute/path/to/folder/, not find . in cron since it won't actually be logging in as you when run from cron.


Perhaps this:

Code:

0 0,12 * * * find /path/to/home -name '*.aud*' | xargs rm

You may need to specify absolute paths to find and xargs and rm, too.

Corona688
Thank you for the quick response.
To illustrate what you recommend i should is the following:
####################
vi maxrm_audfile.ksh
#!/bin/bash
0 0,12 * * * find /opt/app/dcweblog/oracle/admin/PW4ARBY/adump -name '*.aud*' | xargs rm.
ls * | wc -l

What if I want the word count after the above command was executed? Can I include
ls * | wc -l as the above?
####################

If it's running automatically, echoing a number likely won't go anywhere. It's possible to arrange it being sent to an email but this depends on the configuration of your server.

And no, you don't put that line in a bash script, you put it in your crontab, which you edit with crontab -e.

Thanks for your response