Cut pid from ps using cut command

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# 1  
Old 03-11-2013
Cut pid from ps using cut command

i am trying to get JUST the PID from the ps command.
my command line is:

ps -ef | grep "mintty" | cut -d' ' -f2
but i get an empty line. i assume that the delimiter is not just one space character, but can't figure out what should i do in order to do that.

i know i can use awk or cut -c1-4 (the pid is in characters 1-4), but i don't want to use them.

is it possible to achieve my goal using cut -f and a combination or -d or -s?

# 2  
Old 03-11-2013
Tools take leading whitespace characters as one empty field, many empty fields or as leading space of the first field. You might use sed, so you can control field definition with regex. The ps output is also problematic as fields change form by value. Newer ps allow you to specify what fields you want with -o.
# 3  
Old 03-11-2013
thanks, but i want to use only ps, grep and cut, is it eve possible the way i started?
# 4  
Old 03-11-2013
Try using awk instead:
ps -ef | awk '/mintty/&&!/awk/{print $2 } '

OR use pgrep
pgrep mintty

This User Gave Thanks to Yoda For This Post:
# 5  
Old 03-11-2013
This is a task tailor-made for pgrep. If you insist on using a ps pipeline, why? Is it a homework assignment? Is pgrep not available? If not, what OS are you using?

# 6  
Old 03-11-2013
Doesn't make sense to say "I want to use only ps, grep and cut".

---------- Post updated at 04:23 PM ---------- Previous update was at 04:20 PM ----------

pgrep - I learned something new. Thanks

I had pidof written down in my notebook. That might work for you.
# 7  
Old 03-11-2013
pgrep is almost certainly more reliable than pidof. I am not absolutely certain, but I believe pidof is only found on Linux systems. pgrep (and pkill) are virtually everywhere.

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