UNIX for Dummies Questions & Answers

Hi,

i am writing a bash file and need to list the command name and user for the busiest process ie the one using the greatest percentage of CPU time)

im kind of stuck. i know you should get the highest CPU , sort column 3 then take off the head but i'm un sure how would i do that?

echo "Busiest command and user:$(ps au | awk '/CPU%/ {print $3})"

thats what i did so far and im sure its wrong.

Any help?

well you're getting close...

few things:

1. you didn't sort it.
2. /CPU%/ would find a line containing CPU%. You want the column, which you already address as $3

Code:

ps au | sort -rnk3,3 | head -1 | awk '{print $3}'

but awk is very powerful. you can find the maximum with it and drop two commands in the pipeline

Code:

$ ps aux | awk '$3 > max {max=$3;user=$1;cmd=$11} END { printf("busiest command: [%s] by user %s\n",cmd,user) }'
busiest command: [openvpn] by user nobody

That first bit of code just returns "0.0"?

The second works but it says the busiest is /Applications/Firefox.app/Contents/MacOS/plugin-container.app/Contents/MacOS/plugin-container] by user Ryoukii

I need it to show the busiest process that is displayed when ps au is used? plugin-container is not there