UNIX for Dummies Questions & Answers

I have an Output file which has the result

Code:

YYYY 95,77
YYYY 
YYYY 95
YYYY 95
YYYY 95
YYYY 95
YYYY 95
YYYY 95
YYYY 95
YYYY 95
YYYY 
YYYY 
YYYY 
YYYY

I would like to display the above along with a single line with above info. Final output should be

Code:

YYYY 95
YYYY 95,77

YYYY has sources 95,77.

I cannot figure a way to delete those line without a number and to display it in a line.

Please help.

With grep and sort

Code:

$ grep "[0-9]" file | sort -u
YYYY 95
YYYY 95,77

with awk

Code:

$ awk '/[0-9]/ && !A[$0]++' file
YYYY 95,77
YYYY 95

Hi thank you. But that is only sorting the file.

But I cannot display this info in one line/

I always get

Code:

 Corresponding Sources
  , , ,1, 196 95 95,77

Any way i can take out those spaces?

---------- Post updated at 09:16 AM ---------- Previous update was at 09:16 AM ----------

Hi thank you. But that is only sorting the file.

But I cannot display this info in one line/

I always get
Corresponding Sources
, , ,1, 196 95 95,77

Any way i can take out those spaces?

I have managed to get the following output:
XPAR
XPAR
XPAR ,
XPAR , ,
XPAR ,1,
XPAR 12
XPAR 19
XPAR 196
XPAR 20
XPAR 95
XPAR 95,
XPAR 95,77

But I would like to just clean up the rows which have no data/ space/ tab on the second column.

Any Ideas please.