Extracting part of a word

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# 1  
Extracting part of a word

I have the code


I want to extract the FG=3605 parts of this. Please help. I am trying to do this using awk or unix.

Last edited by Scrutinizer; 01-28-2013 at 10:56 AM.. Reason: code tags
# 2  
Does the data always appear in this format (i.e. the FG=<someval>) prior to the closing brace?

If so

$ echo "message={TP=2012:09:23:00:00:00:GMT,SD=2012:09:23:00:00:00:GMT,SP=2,FT=CCGT,FG=3605}" | sed 's/^.*,\(FG=[^}]*\)}.*$/\1/'

will do the trick ...
# 3  
If I have a file that contains multiple lines of the same format, is there a way to extract all the FG=???? at the same time and save to a new file? thanks
# 4  
If position is reliable
$ FG=$(echo 'message={TP=2012:09:23:00:00:00:GMT,SD=2012:09:23:00:00:00:GMT,SP=2,FT=CCGT,FG=3605}' | awk -F\, '{print $NF}'|  sed 's/\}//g')

$ echo $FG

# 5  
Yup - many ways to skin the cat.

As for the question about multiple lines - yes

bash-3.2$  sed 's/^.*,\(FG=[^}]*\)}.*$/\1/' input_file > output_file

Even works over multiple files:

bash-3.2$ for i in 1 2 3 4; do
> echo "message={TP=2012:09:23:00:00:00:GMT,SD=2012:09:23:00:00:00:GMT,SP=2,FT=CCGT,FG=360${i}}" > file_${i}
> done
bash-3.2$ sed 's/^.*,\(FG=[^}]*\)}.*$/\1/' file_{1,2,3,4} > foo.txt
bash-3.2$ cat foo.txt

# 6  
Thank you

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